A mercury drop of radius 10 -3 m is broken into 125 equal size droplets. Surface tension of mercury is 0.45 Nm -1 . The gain in surface energy is:
Text Solution
Verified by ExpertsThe correct answer is:
A
Initial surface energy = 0.45 x 4 
(10 -3 ) 2
So, final surface energy = 0.45 x 125 x 
Increase in energy = 0.45 x 471 x (10 -3 ) 2 
= 4x0.45 x4 
x 10 -6
= 2.26 x 10 -5 J
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